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9x^2+36x=72
We move all terms to the left:
9x^2+36x-(72)=0
a = 9; b = 36; c = -72;
Δ = b2-4ac
Δ = 362-4·9·(-72)
Δ = 3888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3888}=\sqrt{1296*3}=\sqrt{1296}*\sqrt{3}=36\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36\sqrt{3}}{2*9}=\frac{-36-36\sqrt{3}}{18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36\sqrt{3}}{2*9}=\frac{-36+36\sqrt{3}}{18} $
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